hydraulic conductivity

  • Post reply
3 replies [Last post]
Thu, 07/15/2010 - 20:03
eyentiowen
Offline
Joined: Jul 15 2010

i can't seem to find a derivation for the hydraulic conductivity applied to transformed section which is given by k' = [(Kx)(Kz)]^(1/2)..
can anyone please help me..


 


S P O N S O R E D    L I N K S
Top
  • 1366 reads
  • Quote
Thu, 07/15/2010 - 23:17
#1
Guest
Re: hydraulic conductivity

What I know for [(Kx)(Kz)]^(1/2) is that it is being used for anisotropic soil in flow nets. Instead of using the flow formula q = k H Nf/Hd, it uses q = H (Nf/Nd) [(Kx)(Kz)]^(1/2) where H head, Nf = flow channels, Nd = pressure drops, and k = permeability coefficient.

Top
  • reply
  • quote
Sat, 05/28/2011 - 20:17
#2
Guest
Re: hydraulic conductivity

just resultant of kx and kz.

Top
  • reply
  • quote
Mon, 08/22/2011 - 07:10
#3
Guest
Re: hydraulic conductivity

yes the resultant indeed

Top
  • reply
  • quote

Post new comment

  • No HTML tags allowed
  • Web page addresses and e-mail addresses turn into links automatically.
  • Lines and paragraphs break automatically.
  • You can use BBCode tags in the text. URLs will automatically be converted to links.

More information about formatting options

CAPTCHA
This question is for testing whether you are a human visitor and to prevent automated spam submissions.
      _              _          _  __ __   __
   __| | __      __ | |   ___  | |/ / \ \ / /
  / _` | \ \ /\ / / | |  / __| | ' /   \ V / 
 | (_| |  \ V  V /  | | | (__  | . \    | |  
  \__,_|   \_/\_/   |_|  \___| |_|\_\   |_|
Enter the code depicted in ASCII art style.